an=3an-1-4,a0=1
an=an−1−4,a0=1a1=a0−4=1−4=−3a2=a1−4=(1−4)−4a3=a2−4=(1−4−4)−4⋮an=1−4na_n=a_{n-1}-4,a_0=1\\ a_1=a_0-4=1-4=-3\\ a_2=a_1-4=(1-4)-4\\ a_3=a_2-4=(1-4-4)-4\\ \vdots\\ a_n=1-4nan=an−1−4,a0=1a1=a0−4=1−4=−3a2=a1−4=(1−4)−4a3=a2−4=(1−4−4)−4⋮an=1−4n
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments