Question

a_n=3a_n-1-4,a₀=1

Answer 1

$a_n=a_{n-1}-4,a_0=1\\ a_1=a_0-4=1-4=-3\\ a_2=a_1-4=(1-4)-4\\ a_3=a_2-4=(1-4-4)-4\\ \vdots\\ a_n=1-4n$