Question #164149

Q(X,y):X+y >or=7 then what is truth value of∀x∃yQ(x,y)


1
Expert's answer
2021-02-22T13:11:41-0500

 The answer depends on the set where the values of x, y are defined. Given ,

Q(x,y):x+y7Q(x,y):x+y\ge7


xyQ(x,y)\forall x \exist yQ(x, y)


For all value of x Let x=1 and y=1:



x+y=1+1=2<7x+y=1+1=2<72 is less than 72\text{ is less than }7

Since x+y7x+y\le7 The truth value of Q is false for some values of x and y.


At x=8,y=2X+y=8+2=10>7\text{At } x=8,y=2\\ X+y=8+2=10>7


then the truth value of Q(x, y) is true for some values of x and y


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