The complete graph k6 has how many different Hamiltonian circuits?
a) 6
b) 720
c) 120
d) 60
1
Expert's answer
2012-10-01T11:22:44-0400
1) Fix the vertex. 2) From each vertex we can go to another, so start on fix vertex. We have 5 ways for start. Next we have 4 (5 - 1 from starting point to this point) ways, next 3, 2, 1. So, we have 5*4*3*2*1 circuits and 6 ways to choose first vertex. Answer 6*5*4*3*2*1=720 - b)
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