Question

Show that among 2000 student in a school, at least six were born on the same day of the leap year

Answer 1

$\text{leap year contains 366 days}$

$\text{according to the dovecote principle there is a day on which }$

$\text{at least }\lceil\frac{2000}{366} \rceil\text{ students were born}$

$\lceil\frac{2000}{366} \rceil=6;\lceil{....} \rceil\text{-round a number up to an integer}$

Answer:proven