Let A={1,2,3}A =\{1,2,3\}A={1,2,3} and B={n∈Z+ ∣ n2<10}B =\{ n\in \mathbb Z_+\ |\ n^2<10\}B={n∈Z+ ∣ n2<10}.
Let us solve the inequality n2<10n^2<10n2<10 for n∈Z+n\in \mathbb Z_+n∈Z+. It followst that ∣n∣<10|n|<\sqrt{10}∣n∣<10 and therefore,n∈(−10,10)∩Z+={1,2,3}.n\in(-\sqrt{10},\sqrt{10})\cap\mathbb Z_+=\{1,2,3\}.n∈(−10,10)∩Z+={1,2,3}. It follows that A=B.A=B.A=B.
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