(a) True. There is a x in R such that x5=−1 , it's x=-1.
(b) True. x6<x4,x4(x2−1)<0,x4<0 has no solutions so x2−1<0,∣x∣<1,−1<x<1. So yes, there is x in R such that x6<x4 .
(c) True. No matter what x is, (−x)4=((−1)⋅x)4=(−1)4⋅x4=1⋅x4=x4 .
(d) False. 2x>x,x>0 . So this statement is true only for positive numbers, not for all x in R
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