Answer to Question #142114 in Discrete Mathematics for Promise Omiponle

Question #142114
Compute the number of distinct arrangements of the characters ABBCCCDDDDEEEEE
1
Expert's answer
2020-11-19T16:34:43-0500

The number of permutations of "n"  objects with "n_1" identical objects of type 1, "n_2" identical objects of type 2, …, and "n_k" identical objects of type k is "\\frac {n!} {n_1!n_2!...n_k!}" . Means number of distinct arrangements is

"\\frac {15!} {1!*2!*3!*4!*5!} = 37\u00a0837\u00a0800"


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