F(x,y)=(x can fool y)F(x,y)=(\text{x can fool y})F(x,y)=(x can fool y)
domain of x="all people in the world"\text{domain of } x = \text{"all people in the world"}domain of x="all people in the world"
domain of y="all people in the world"\text{domain of } y = \text{"all people in the world"}domain of y="all people in the world"
∀x∃yF(x,y)\forall{x}\exists{y}F(x,y)∀x∃yF(x,y)
Answer: ∀x∃yF(x,y)\forall{x}\exists{y}F(x,y)∀x∃yF(x,y)
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