A={1,2 3,4,5,6}
{(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3)(3,4),(3,5)(3,6)}
R={(2,1)(3,2)}
1
"\\forall a \\isin A" ",(a,a)\\notin R"
(1,1)(2,2)(3,3)"\\notin" R
This is not reflexive
2 (a,b)"\\isin" R but (b,a)"\\notin" R
(2,1)"\\isin" R but (1,2)"\\notin" R
SO this is antisymmetric
3 (a,b)"\\isin" R
(b,c)"\\isin" R
(c,a)"\\isin" R
This is a transitive property.
So this is not an equivalance relation.
Comments
Leave a comment