f(0)=5f(0)=5f(0)=5
f(2)=f(0)+5=5+5=10f(2)=f(0)+5=5+5=10f(2)=f(0)+5=5+5=10
f(4)=15f(4)=15f(4)=15
If n is even then f(n)=5∗(n/2+1)f(n)=5*(n/2 + 1)f(n)=5∗(n/2+1)
f(14)=5∗(14/2+1)=5∗8=40f(14)=5*(14/2 + 1)=5 * 8=40f(14)=5∗(14/2+1)=5∗8=40
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