a) Q(0) is false because "0+1 \\neq 2 \\cdot 0";
b) Q(-1) is false because "-1+1 \\neq 2 \\cdot (-1)";
c) Q(1) is true because "1+1 = 2 \\cdot 1";
d) "\\exists xQ(x)" is true because there exists x (x=1) that makes statement Q(x=1) to be true;
e) "\\forall xQ(x)" is false because Q(x) is not true for all x, see a) and b)
f) "\\lnot \\forall xQ(x) = \\exist x \\lnot Q(x)" is true because there exists such a x for which Q(x) is not true, e.g. a) and b)
g) "\\exist x \\lnot Q(x)" is true the same as f)
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Let H(x) be the statement “x is hardworking”, N(x) be the statement “x is naughty” and C(x) be the statement “ x is clever”, where the domain for x consists of all students. Use quantifications to express each of the following statements. a) Some students are clever but naughty. b) Not all students are clever and hardworking. c) Some students are clever, hardworking and not naughty. d) All students are clever, or hardworking or naughty.
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