(i) R1 = {(2,x), (y,4), (6,z)}
In R1 : it is not reflexive ,because (a,a)"\\notin" R
IN R1:it is antisymmetric, (a,b) (b,a)"\\in" R "\\implies"
a=b
In R1 : it is transitivity (a,b)(b,c)"\\implies" (a c)
In relation (2,x) given but not continue to x
(X,?)
so this is transitivity
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