(i) Take (x,y)∈A×B. Then x∈A and y∈B, hence by A⊂C and B⊂D we have x∈C and y∈D. This implies that (x,y)∈C×D, which gives A×B⊂C×D.
(ii) By definition, A×B={(a,y),(a,z),(b,y),(b,z),(c,y),(c,z),(d,y),(d,z)} and B×A={(y,a),(z,a),(y,b),(z,b),(y,c),(z,c),(y,d),(z,d)}
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