Question #125569

(i) Show that if A ⊆ C and B ⊆ D, then A×B ⊆ C ×D
(ii) Let A ={a , b , c ,d}and B ={y , z}. Find (a) A×B (b) B×A

Expert's answer

(i) Take (x,y)∈A×B(x,y)\in A\times B. Then x∈Ax\in A and y∈By\in B, hence by A⊂CA\subset C and B⊂DB\subset D we have x∈Cx\in C and y∈D.y\in D. This implies that (x,y)∈C×D(x,y)\in C\times D, which gives A×B⊂C×DA\times B\subset C\times D.

(ii) By definition, A×B={(a,y),(a,z),(b,y),(b,z),(c,y),(c,z),(d,y),(d,z)}A\times B=\{(a,y),(a,z),(b,y),(b,z),(c,y),(c,z),(d,y),(d,z)\} and B×A={(y,a),(z,a),(y,b),(z,b),(y,c),(z,c),(y,d),(z,d)}B\times A=\{(y,a),(z,a),(y,b),(z,b),(y,c),(z,c),(y,d),(z,d)\}


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