1.
We have relation: "\\{(m,n):6|n-m\\}"
It is equivalence relation.
Reflexivity: since "m-m=0" and "6|0" , then "m(mod6)=m"
Symmetry: since "n-m=-(m-n)" , then "6|(m-n)" and "n=m(mod6)"
Transitivity: if "m=n(mod6)" and "n=k(mod6)" then "6|(n-m),6|(k-n)" .
Since "k-m=(k-n)+(n-m)" we have "6|(k-m)" and "m=k(mod6)"
Partition is:
"[m]=\\{n-6a\\}" , where "a\\in N"
2.
a) Relation "less than" on the set N is not equivalence relation:
No reflexivity: a number cannot be less than itself.
No symmetry: if "a<b" then "b>a"
Transitivity: if "a<b" and "b<c" then "a<c"
b) Relation "has the same shape as" on the set of all triangles is equivalence relation:
Reflexivity: one triangle has single shape
Symmetry: two triangles can have same shape
Transitivity: three triangles can have same shape
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