Question #56120

Given that
A=sinti+costj+tk
, find
∣∣∣d^2A/dt^2∣∣∣
7
3
2
1
1

Expert's answer

2015-12-02T11:14:53-0500

Answer on Question #56120 – Math – Differential Geometry

Question

A=sinti+costj+tk

, find

//d^2A/dt^2//

7

3

2

1

Solution

dAdt=costisintj+k\frac {d A}{d t} = \cos t i - \sin t j + kd2Adt2=sinticostj+0k\frac {d ^ {2} A}{d t ^ {2}} = - \sin t i - \cos t j + 0 kd2Adt2=sin2t+cos2t=1\left| \left| \frac {d ^ {2} A}{d t ^ {2}} \right| \right| = \sqrt {\sin^ {2} t + \cos^ {2} t} = 1


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