Question #19020

if A_{ij} is a skew-symmetric tensor,then show that (B^i_jB^k_p+B^i_pB^k_j)A_ik=0
1

Expert's answer

2012-11-22T07:48:13-0500

Question 19020

For skew-symmetric tensor Aik=AkiA_{ik} = -A_{ki} . Hence,


BijBkpAik+BipBkjAik=BijBkpAik+BkpBijAki=BijBkpAikBkpBijAik=0.B _ {i j} B _ {k p} A _ {i k} + B _ {i p} B _ {k j} A _ {i k} = B _ {i j} B _ {k p} A _ {i k} + B _ {k p} B _ {i j} A _ {k i} = B _ {i j} B _ {k p} A _ {i k} - B _ {k p} B _ {i j} A _ {i k} = 0.

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