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Solve the differential equation y'=x(1+y^2)
If (y=2x+ce^x) is a solution of the differential equation frac {dy}{dx}-y=2(1-x) then find the particular solution satisfied by x=0, y=3
Obtain the solution for the initial value problem y'+(cotx)y=xcscx, y left frac{pi}{2} right=1
Solve the equation xfrac{dy}{dx}-ay=x+1 where a is a constant
The general solution of the equation is y'+(cotx)y=xcscx
Use the separable method to solve the differential equation fracdydx=xy
Solve the equation y'=x(1+y^2) by using variable separable
Find the general solution frac{dy}{dx}= frac{2y^2+3xy}{x^2}
Using integrating factor, solve the differential equation frac {dy}{dx}+y=e^{x}
(3x+y-z)p+(x+y-z)q=2(z-y)
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