Question #96318
Use the separable method to solve the differential equation fracdydx=xy
1
Expert's answer
2019-10-14T11:53:59-0400

Solution: The differential equation using separable method:

dydx=xy\frac{dy}{dx} = xy

The equation can be written as follows:


dyy=xdx\frac{dy}{y} = x dx

We can now integrate both sides:

dyy=xdx\int \frac{dy}{y} = \int x dx


lny=12x2+C1\ln y = \frac{1}{2}x^2 + C_1

lny=lne12x2+C1\ln y = \ln e^{\frac{1}{2}x^2 + C_1}

y=e12x2+C1=e12x2eC1=Ce12x2,y = e^{\frac{1}{2}x^2 + C_1} = e^{\frac{1}{2}x^2} e^{C_1} = C e^{\frac{1}{2}x^2},


where C1C_1 and C=eC1C = e^{C_1} are constants.


Answer:

y=Ce12x2y = C e^{\frac{1}{2}x^2}


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS