Let us rewrite the differential equation in form "dy = (2 x^2 + 3 x + 2 ) dx", and integrate both sides: "y = \\int dy = \\int (2 x^2 + 3 x + 2 ) dx =\\frac{2}{3} x^3 + \\frac{3}{2} x^2 + 2 x + C".
Substituting the boundary condition "y(1) = 4" into last equation, obtain "4 = \\frac{25}{6} + C", from where "C = -\\frac{1}{6}". Hence, the solution of given differential equation is "y(x) = \\frac{2}{3}x^3 + \\frac{3}{2} x^2 + 2 x - \\frac{1}{6}" .
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