Question #89432

solve the equation d2^t/dx2-4t=0

Expert's answer

Answer to Question #89432 – Math – Differential Equations

Question

1. Solve the equation d2tdx24t=0\frac{d^2t}{dx^2} - 4t = 0.

Solution


d2tdx24t=0\frac{d^2 t}{d x^2} - 4 t = 0(D24)t=0(D^2 - 4) t = 0


where, D2d2dx2D^2 \equiv \frac{d^2}{d x^2}.

The auxiliary equation is m24=0m^2 - 4 = 0

m=±2\therefore m = \pm 2


Thus, the required solution for the given differential equation is,


t(x)=c1e2x+c2e2x.t(x) = c_1 e^{2x} + c_2 e^{-2x}.


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