Answer to Question #89432 – Math – Differential Equations
Question
1. Solve the equation dx2d2t−4t=0.
Solution
dx2d2t−4t=0(D2−4)t=0
where, D2≡dx2d2.
The auxiliary equation is m2−4=0
∴m=±2
Thus, the required solution for the given differential equation is,
t(x)=c1e2x+c2e−2x.
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