Question #85724

The given family of functions is the general solution of the differential equation on the indicated interval. Find a member of the family that is a solution of the initial-value problem.
y = c1ex + c2e−x, (−∞, ∞); y'' − y = 0, y(0) = 0, y'(0) = 7

Expert's answer

Answer on question #85724 – Math – Differential Equations

Let y(x)=C1ex+C2exy(x) = C_1 e^x + C_2 e^{-x}. The condition of yy=0y^{\wedge} - y = 0 is satisfied for all xx: y=C1exC2exy^{\wedge} = C_1 e^x - C_2 e^{-x}, y=C1ex+C2ex=yy^{\wedge \wedge} = C_1 e^x + C_2 e^{-x} = y.

From a condition of y(0)=0y(0) = 0 we receive C2=C1C_2 = -C_1 and from y(0)=7y^{\wedge}(0) = 7 we receive 2C1=72C_1 = 7. So, C1=3.5C_1 = 3.5, C2=3.5C_2 = -3.5, hence y(x)=3.5ex3.5exy(x) = 3.5 e^x - 3.5 e^{-x}.

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