Answer on question #85724 – Math – Differential Equations
Let y(x)=C1ex+C2e−x. The condition of y∧−y=0 is satisfied for all x: y∧=C1ex−C2e−x, y∧∧=C1ex+C2e−x=y.
From a condition of y(0)=0 we receive C2=−C1 and from y∧(0)=7 we receive 2C1=7. So, C1=3.5, C2=−3.5, hence y(x)=3.5ex−3.5e−x.
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