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Answer to Question #84506 in Differential Equations for Ra
Question #84506
Show that:
i) J_1/2(x)=√(2/πx)cosx
ii) d/dx[xJ_1(x)]=xJ_0(x)
i) J_1/2(x)=√(2/πx)cosx
ii) d/dx[xJ_1(x)]=xJ_0(x)
Expert's answer
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