Question #83980

Prove that for a two dimensional motion to be possible the stream function and the velocity Potential satisfy the cauchys-Riemanns Equation. Moreover, deduce that both satisfies laplaces equatiin

Expert's answer

Answer to the question 83980, Math / Differential Equations

Denote by v=(v1,v2)\overline{v} = (v_{1}, v_{2}) the stream function. Since the flow is incompressible we have div(v)=0div(\overline{v}) = 0. Since it is potential we have that there exists the velocity potential uu such that v1=ux1v_{1} = \frac{\partial u}{\partial x_{1}}, v2=ux2v_{2} = \frac{\partial u}{\partial x_{2}}. Thus from div(v)=0div(\overline{v}) = 0 we obtain that Δu=0\Delta u = 0. As v1=ux1v_{1} = \frac{\partial u}{\partial x_{1}} we also have Δv1=0\Delta v_{1} = 0. As v2=ux2v_{2} = \frac{\partial u}{\partial x_{2}} we also have Δv2=0\Delta v_{2} = 0.

From div(v)=0div(\overline{v}) = 0 we have v1x1=v2x2\frac{\partial v_1}{\partial x_1} = -\frac{\partial v_2}{\partial x_2}. From v1=ux1v_1 = \frac{\partial u}{\partial x_1}, v2=ux2v_2 = \frac{\partial u}{\partial x_2} we have v1x2=v2x1\frac{\partial v_1}{\partial x_2} = \frac{\partial v_2}{\partial x_1}. Thus we obtain also Cauchy-Riemann equations.

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