Question #82190

Obtain the solution of the equation.
xy'=4y.

Expert's answer

Answer on Question #82190 – Math – Differential Equations

Question

Obtain the solution of the equation.


xy=4y.x y ^ {\prime} = 4 y.

Solution

xy=4y;x y ^ {\prime} = 4 y;


In this ODE we can do a separation of variables.


xdydx=4y;dydx=4yx;dyy=4dxx;dyy=4dxx;lny=4lnx+A;\begin{array}{l} x \frac {d y}{d x} = 4 y; \\ \frac {d y}{d x} = \frac {4 y}{x}; \\ \frac {d y}{y} = 4 \frac {d x}{x}; \\ \int \frac {d y}{y} = 4 \int \frac {d x}{x}; \\ \ln y = 4 \ln x + A; \\ \end{array}


where AA is a some constant. We can rewrite it:


A=4lnB;A = 4 \ln B;


where BB is another constant. Therefore, we have


lny=4lnx+4lnB=4ln(Bx)=ln(Bx)4=ln(Cx4);\ln y = 4 \ln x + 4 \ln B = 4 \ln (B x) = \ln (B x) ^ {4} = \ln (C x ^ {4});


where C=B4C = B^4

Finally,


y(x)=Cx4.y (x) = C x ^ {4}.


Answer: y=Cx4y = C x^4

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