Answer on Question #77428 – Math – Differential Equations
Question
dx2d2y+3dxdy+2y=1+3x+x2.
Solution
The corresponding homogeneous equation is dx2d2y+3dxdy+2y=0 . So, characteristic equation will be
r2+3r+2=(r+1)(r+2)=0.
Then the complementary solution will be
yc=C1e−x+C2e−2x.
The nonhomogeneous equation has f(x)=1+3x+x2 . We will search a particular solution in the next general quadratic polynomial form:
yp=A+Bx+Cx2.
Then dxdy=B+2Cx and dx2d2y=2C . Substitute them into the equation:
2C+3(B+2Cx)+2(A+Bx+Cx2)=1+3x+x2.
The corresponding terms on both sides should have the same coefficients. Hence, we obtain:
2C=1,6C+2B=3,2C+3B+2A=1.
Now we have the next solution for unknown coefficients:
C=21,B=0,A=0.
The general solution of equation is
y=yc+yp=C1e−x+C2e−2x+2x2.
Answer: y=C1e−x+C2e−2x+2x2 .
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