Question #69652

Find the value of m so that the functiony=emx is a solution of the differential equation y′+2y=0

Expert's answer

Answer on Question #69652 – Math – Differential Equations

Question

Find the value of mm so that the function y=emxy = e^{mx} is a solution of the differential equation


y+2y=0y' + 2y = 0

Solution

y=memxy' = m e^{mx}memx+2emx=0m e^{mx} + 2 e^{mx} = 0emx(m+2)=0e^{mx}(m + 2) = 0emx0, soe^{mx} \neq 0, \text{ so}m=2m = -2


Answer: m=2m = -2.

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