Question #69639

Find the solution of y′=2xy2

Expert's answer

Answer on Question #69639 – Math – Differential Equations

Question

Find the solution of


y=2xy2y' = 2xy^2

Solution

y=2xy2,y' = 2xy^2,dy/dx=2xy2,dy/dx = 2xy^2,1/y2dy=2xdx,1/y^2 \cdot dy = 2x \cdot dx,1/y2dy=2xdx,\int 1/y^2 \cdot dy = \int 2x \cdot dx,1/y+C=x2,-1/y + C = x^2,


where CC is constant of integration,


y=1/(Cx2).y = 1/(C - x^2).


Answer: y=1/(Cx2)y = 1/(C - x^2).

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