Question #69628

Solve the initial value problem y′−ay=0,y(x0)=y0

Expert's answer

Answer on Question #69628 – Math – Differential Equations

Question

Solve the initial value problem yay=0y' - ay = 0, y(x0)=y0y(x_0) = y_0

Solution

yay=0,(1)y' - ay = 0, \quad (1)y(x0)=y0.(2)y(x_0) = y_0. \quad (2)


Equation (1) is a first-order linear ordinary differential equation, its general solution is given by


y=Ceax,(3)y = C \cdot e^{ax}, \quad (3)


where CC is an arbitrary real constant.

Substituting for yy from (3) into (2)


y(x0)=Ceax0=y0C=y0eax0y=y0eax0eax=y0ea(xx0)y(x_0) = C \cdot e^{ax0} = y_0 \quad \Rightarrow \quad C = y_0 \cdot e^{-ax0} \quad \Rightarrow \quad y = y_0 \cdot e^{-ax0} \cdot e^{ax} = y_0 \cdot e^{a(x \cdot x_0)}


Answer: y=y0ea(xx0)y = y_0 \cdot e^{a(x \cdot x_0)}

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