Answer on Question #69628 – Math – Differential Equations
Question
Solve the initial value problem y′−ay=0, y(x0)=y0
Solution
y′−ay=0,(1)y(x0)=y0.(2)
Equation (1) is a first-order linear ordinary differential equation, its general solution is given by
y=C⋅eax,(3)
where C is an arbitrary real constant.
Substituting for y from (3) into (2)
y(x0)=C⋅eax0=y0⇒C=y0⋅e−ax0⇒y=y0⋅e−ax0⋅eax=y0⋅ea(x⋅x0)
Answer: y=y0⋅ea(x⋅x0)
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