Answer to Question #69469 in Differential Equations for Osat

Question

Suppose
y
=
2
e
−
4
x
y=2e−4x
is the solution to the initial value problem
y
′
+
k
y
=
0
,
y
(
0
)
=
y
0
y′+ky=0,y(0)=y0
. Find the value of
y
0