Answer on Question #68370 – Math – Differential Equations
Question
Form Partial differential eq. of x2/a2+y2/b2+u2/c2=1
Solution
We have the following equation
a2x2+b2y2+c2u2=1
Note that the number of constants (a,b,c) is more than the number of independent variables (x,y). Hence the order of the resulting differential equation will be more than 1.
Differentiating (1) partially with respect to x we get
a22x+c22u∂x∂u=0
or
a2c2=−xu∂x∂u
Differentiating (2) partially with respect to x we get
a21+c21∂x∂u∂x∂u+c2u∂x2∂2u=0
or
a2c2=−(∂x∂u)2−u∂x2∂2u
From (3) and (4) we get
xu∂x2∂2u+x(∂x∂u)2=u∂x∂u
which is required differential equation.
This equation is not unique. Similarly differentiating (1) partially with respect to y we get
b22y+c22u∂y∂u=0
or
b2c2=−yu∂y∂u
and differentiating (6) partially with respect to y we get
b21+c21∂y∂u∂y∂u+c2u∂y2∂2u=0
or
b2c2=−(∂y∂u)2−u∂y2∂2u
From (7) and (8) we get
yu∂y2∂2u+y(∂y∂u)2=u∂y∂u
which is also a required differential equation. Equations (5) and (9) can be summed so that the resulting equation is symmetric with respect to x and y
xu∂x2∂2u+yu∂y2∂2u+x(∂x∂u)2+y(∂y∂u)2=u∂x∂u+u∂y∂u
Answer: The required partial differential equations are
xu∂x2∂2u+x(∂x∂u)2=u∂x∂u
or
yu∂y2∂2u+y(∂y∂u)2=u∂y∂u
or
xu∂x2∂2u+yu∂y2∂2u+x(∂x∂u)2+y(∂y∂u)2=u∂x∂u+u∂y∂u
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