Question #68368

Form Partial differential eq. of u=xy+y√(x^2-a^2 )+b

Expert's answer

Answer on Question #68368 – Math – Differential Equations

Question

Form Partial differential eq. of u=xy+y(x2a2)+bu = xy + y\sqrt{(x^2 - a^2)} + b

Solution


u=xy+yx2a2+bp=ux=y+xyx2a2q=uy=x+x2a2x2a2=qxp=y+xyqx\begin{array}{l} u = x y + y \sqrt {x ^ {2} - a ^ {2}} + b \\ p = \frac {\partial u}{\partial x} = y + \frac {x y}{\sqrt {x ^ {2} - a ^ {2}}} \\ q = \frac {\partial u}{\partial y} = x + \sqrt {x ^ {2} - a ^ {2}} \\ \sqrt {x ^ {2} - a ^ {2}} = q - x \rightarrow p = y + \frac {x y}{q - x} \\ \end{array}


A partial differential equation (PDE) is


p=y+xyqx,p = y + \frac {x y}{q - x},


that is,


ux=y+xyuyx\frac {\partial u}{\partial x} = y + \frac {x y}{\frac {\partial u}{\partial y} - x}


Answer: p=y+xyqxp = y + \frac{xy}{q - x} or ux=y+xyuyx\frac{\partial u}{\partial x} = y + \frac{xy}{\frac{\partial u}{\partial y} - x}.

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