Question #64250

If y= e ax cos 3 x sin 2 x find dy/dx

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Answer on Question #64250 – Math – Differential Equations

Question

If y=eaxcos(3x)sin(2x)y = e^{ax}\cos(3x)\sin(2x) find dydx\frac{dy}{dx}

Solution

Recall the following formulae:


(uv)=uv+uv(f(g(x)))=f(g(x))g(x)(ex)=ex(sin(x))=cos(x)(cos(x))=sin(x)(ax)=a\begin{array}{l} (uv)' = u'v + uv' \\ \left(f(g(x))\right)' = f'(g(x)) \cdot g'(x) \\ (e^x)' = e^x \\ (\sin(x))' = \cos(x) \\ (\cos(x))' = -\sin(x) \\ (ax)' = a \\ \end{array}


Then


(eaxsin(2x)cos(3x))=([eaxsin(2x)]cos(3x))=(cos(3x))(eaxsin(2x))+(cos(3x))(eaxsin(2x))==(3sin(3x))(eaxsin(2x))+(cos(3x))(aeaxsin(2x)+2eaxcos(2x))==3sin(3x)sin(2x)eax+aeaxsin(2x)cos(3x)+2eaxcos(2x)cos(3x).\begin{array}{l} (e^{ax} \cdot \sin(2x) \cdot \cos(3x))' = ([e^{ax} \cdot \sin(2x)] \cdot \cos(3x))' = (\cos(3x))' \cdot (e^{ax} \cdot \sin(2x)) + (\cos(3x)) \cdot (e^{ax} \cdot \sin(2x))' = \\ = (-3\sin(3x)) \cdot (e^{ax} \cdot \sin(2x)) + (\cos(3x)) \cdot (ae^{ax} \cdot \sin(2x) + 2e^{ax} \cdot \cos(2x)) = \\ = -3\sin(3x) \cdot \sin(2x) \cdot e^{ax} + ae^{ax} \cdot \sin(2x) \cdot \cos(3x) + 2e^{ax} \cdot \cos(2x) \cdot \cos(3x). \end{array}


**Answer**: 3sin(3x)sin(2x)eax+aeaxsin(2x)cos(3x)+2eaxcos(2x)cos(3x)-3\sin(3x) \cdot \sin(2x) \cdot e^{ax} + ae^{ax} \cdot \sin(2x) \cdot \cos(3x) + 2e^{ax} \cdot \cos(2x) \cdot \cos(3x).


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