Answer on Question #62147 – Math – Differential Equations
Question
Which of the following represent the solution of the differential equation d2y/dx2+4y=0
5tan2x+5cos2x
5sin2x+4cos2x
5sin2x-3cos2x
5sin^22x-3cos2x
Solution
The differential equation
dx2d2y+4y=0
has the characteristic equation
λ2+4=0,
its roots are
λ1=2i,λ2=−2i.
Hence the solution of the differential equation (1) is
y=C1sin(2x)+C2cos(2x);
So, y=5sin2x+4cos2x and y=5sin2x−3cos2x can be solutions of the differential equation (1).
Answer: y=5sin2x+4cos2x;y=5sin2x−3cos2x.
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