Question

suppose f(x,y) =x^3y^2 - sin^2xcos2y, what is df/dy?

Answer 1

Answer on Question #58237 – Math – Calculus

Question

Suppose $f(x,y) = x^3 y^2 - \sin^2 x \cos 2y$, what is $\frac{df}{dy}$?

Solution

If $f(x,y) = x^3 y^2 - \sin^2 x \cos 2y$, then

$$\frac{\partial f}{\partial y} = 2 x^3 y - \sin^2 x \cdot (-\sin(2y)) \cdot 2 = 2 (y x^3 + \sin^2 x \sin 2y).$$

Answer: $\frac{\partial f}{\partial y} = 2 (y x^3 + \sin^2 x \sin 2y)$.

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