Question #49496

If w=f S{xy/( x^2+y^2) } show that x.∂w/∂x + y.∂w/∂y =0

Expert's answer

Answer on Question #49496 – Math – Differential Calculus | Equations

Task:

If w={xy/(x2+y2)}w = \{xy / (x^2 + y^2) \} show that xwx+ywy=0x \frac{\partial w}{\partial x} + y \frac{\partial w}{\partial y} = 0.

Solution:

wx=y(x2+y2)2x2y(x2+y2)2\frac{\partial w}{\partial x} = \frac{y(x^2 + y^2) - 2x^2y}{(x^2 + y^2)^2}wy=x(x2+y2)2y2x(x2+y2)2\frac{\partial w}{\partial y} = \frac{x(x^2 + y^2) - 2y^2x}{(x^2 + y^2)^2}xwx+ywy=xy(x2+y2)2x3y(x2+y2)2+yx(x2+y2)2y3x(x2+y2)2=2yx(x2+y2)2x3y2y3x(x2+y2)2==2xy(x2+y2)x2y2(x2+y2)2=0\begin{aligned} x \frac{\partial w}{\partial x} + y \frac{\partial w}{\partial y} &= \frac{xy(x^2 + y^2) - 2x^3y}{(x^2 + y^2)^2} + \frac{yx(x^2 + y^2) - 2y^3x}{(x^2 + y^2)^2} = \frac{2yx(x^2 + y^2) - 2x^3y - 2y^3x}{(x^2 + y^2)^2} = \\ &= 2xy \frac{(x^2 + y^2) - x^2 - y^2}{(x^2 + y^2)^2} = 0 \end{aligned}


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