Question #47148

Differentiate with respect to x:f(x)=(x+X^5)

1−5x^2
1+5x^4
5x^4−1
x−5x^4

Expert's answer

Answer on Question #47148 – Math - Differential Calculus | Equations

Differentiate with respect to x:f(x)=(x+X5)x: f(x) = (x + X^5)

```

1-5x^2

1+5x^4

5x^4-1

x-5x^4

```

Solution:

We have if


f(x)=axnf(x) = a * x^n


then


f(x)=naxn1.f'(x) = n * a * x^{n-1}.


So we have


f(x)=x+x5f(x) = x + x^5


Hence


f(x)=1+5x4.f'(x) = 1 + 5 * x^4.


Answer: 1+5x41 + 5x^4

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