Question

Findf(x)=x^3n

3nx^3n
3nx^(3n−1)
3nx
3nx^(3n−3)

Answer 1

Answer on Question #47144 – Math – Differential Calculus | Equations

Question:

Find $f'(x) = x^3(n)$

3nx^3(n)

3nx^(3n-1)

3nx

3nx^(3n-3)

Solution:

Apply the power rule:

$$(x^a)' = ax^{a-1}$$

Therefore

$$f'(x) = (x^{3n})' = 3nx^{3n-1}$$

Answer: $3nx^{3n-1}$

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