Answer on Question #47080 – Math – Differential Calculus | Equations
Question. Differentiate with respect to xxx, f(x)=tanxf(x) = \tan xf(x)=tanx
a) (secx)2(\sec x)^2(secx)2
b) (cscx)2(\csc x)^2(cscx)2
c) 2x2−22x^{2} - 22x2−2
d) (cosx)2(\cos x)^2(cosx)2
Solution. (tanx)/1(cosx)2=(secx)2(\tan x) / \frac{1}{(\cos x)^2} = (\sec x)^2(tanx)/(cosx)21=(secx)2
Answer. a) (secx)2(\sec x)^2(secx)2
www.AssignmentExpert.com
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!