Question #47073

If y=5e^x/cosx,differentiate with respect to x.

A. 5e^x(cosx+sinx)/cos^2x

B. e^x(cosx+sinx)/cos^2x

C. 5e^x(cosx+sinx)/cos^3x

D. 5e(cosx+sinx)/cos^2x

Expert's answer

Answer on Question #47073 – Math – Differential Calculus – Equations

Question.

If y=5excosxy = \frac{5e^x}{\cos x} differentiate with respect to xx.

A. 5ex(cosx+sinx)(cosx)2\frac{5e^x(\cos x + \sin x)}{(\cos x)^2}

B. ex(cosx+sinx)(cosx)2\frac{e^x(\cos x + \sin x)}{(\cos x)^2}

C. 5ex(cosx+sinx)(cosx)3\frac{5e^x(\cos x + \sin x)}{(\cos x)^3}

D. 5e(cosx+sinx)(cosx)2\frac{5e(\cos x + \sin x)}{(\cos x)^2}

Solution.

y=(5ex)/cosx5ex(cosx)(cosx)2=5excosx+5exsinx(cosx)2=5ex(cosx+sinx)(cosx)2.y' = \frac{(5e^x)/\cos x - 5e^x(\cos x)}{(\cos x)^2} = \frac{5e^x \cos x + 5e^x \sin x}{(\cos x)^2} = \frac{5e^x (\cos x + \sin x)}{(\cos x)^2}.


We applied differentiation rule for quotient.

Answer.

A. 5ex(cosx+sinx)(cosx)2\frac{5e^x(\cos x + \sin x)}{(\cos x)^2}

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