Question

Find the dy/dx, ify=(sinx)^−1

tanx
cosx
cos^2
sinx

Answer 1

47072, Math, Differential Calculus

Find the $\frac{dy}{dx}$ , if $y = (\sin x)^{-1}$

Solution:

$$y ^ {\prime} = \left((\sin x) ^ {- 1}\right) ^ {\prime} = - \frac {1}{(\sin x) ^ {2}} \cdot \cos x = (\cot x) \cdot (\csc x)$$

Answer: $(\cot x)\cdot (\csc x)$

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