Question #47070

If y =cosx.sinx, differentiate with respect to x.

cos^2x−sin^2x
sin2x
cos^2x+sin^2x
cos2x

Expert's answer

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Answer on Question # 47070 – Math – Differential Calculus | Equations

Task:

If y=cosxsinxy = \cos x \sin x, differentiate with respect to xx.

A. cos2xsin2x\cos^2 x - \sin^2 x

B. sin2x\sin 2x

C. cos2x+sin2x\cos^2 x + \sin^2 x

D. cos2x\cos 2x

Solution:

ddxy=ddx(cosxsinx)=sinxddx(cosx)+cosxddx(sinx)=sin2x+cos2x=cos(2x)\frac{d}{dx} y = \frac{d}{dx} (\cos x \sin x) = \sin x \frac{d}{dx} (\cos x) + \cos x \frac{d}{dx} (\sin x) = - \sin^2 x + \cos^2 x = \cos (2x)


We applied differentiation rule for product of functions.

Thus, two answers ( A. cos2xsin2x\cos^2 x - \sin^2 x and D. cos2x\cos 2x ) are correct.


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