Question

Find the dy/dx,ify=(sinx)^−1

tanx
cosx
cos^2
sinx

Answer 1

Answer on Question #47032 – Math - Differential Calculus | Equations

Find the dy/dx, if $y = (\sin x)^\wedge - 1$.

Solution.

$$\frac{dy}{dx} = \frac{d}{dx} \left( \frac{1}{\sin(x)} \right) = \frac{d (\sin(x))^{-1}}{dx} = - \frac{(\sin(x))'}{\sin^2(x)} = - \frac{\cos(x)}{\sin^2(x)}.$$

Answer: $-\frac{\cos(x)}{\sin^2(x)}$.

www.AssignmentExpert.com