Answer on Question #47031, Math, Differential Calculus
If y=x5⋅ex, differentiate with respect to x
a) xx⋅ex
b) x4⋅ex(x−5)
c) x4x
d) x4⋅ex(x+5)
Solution:
y′=(x5⋅ex)′=(x5)′⋅ex+x5⋅(ex)′=5x4ex+x5ex=x4ex(5+x)
Answer: d) x4⋅ex(x+5)
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