Question #37499 - Mathematics - Differential Calculus
Find the derivative of
i) cosmx
ii) cos2x
Solution:
i) cosmx
Using
dxdcosx=−sinx
The chain rule
If h(x)=f(g(x)), then
dxdh=dgdh⋅dxdg
Constant division rule
dxdah(x)=adxdh(x)dxdcosmx=−msinmx
ii) cos2x
Using
Power rule
dxdxn=nxn−1
The chain rule
If h(x)=f(g(x)), then
dxdh=dgdh⋅dxdgdθdcosx=−sinxdxdcos2x=−2cosxsinx