Question #37499

find the derivative of i) cosmx ii) cospow(2)x

Expert's answer

Question #37499 - Mathematics - Differential Calculus

Find the derivative of

i) cosmx\cos mx

ii) cos2x\cos^2 x

Solution:

i) cosmx\cos mx

Using


ddxcosx=sinx\frac{d}{dx} \cos x = -\sin x


The chain rule

If h(x)=f(g(x))h(x) = f(g(x)), then


dhdx=dhdgdgdx\frac{dh}{dx} = \frac{dh}{dg} \cdot \frac{dg}{dx}


Constant division rule


ddxah(x)=addxh(x)\frac{d}{dx} ah(x) = a \frac{d}{dx} h(x)ddxcosmx=msinmx\frac{d}{dx} \cos mx = -m \sin mx


ii) cos2x\cos^2 x

Using

Power rule


dxndx=nxn1\frac{dx^n}{dx} = nx^{n-1}


The chain rule

If h(x)=f(g(x))h(x) = f(g(x)), then


dhdx=dhdgdgdx\frac{dh}{dx} = \frac{dh}{dg} \cdot \frac{dg}{dx}ddθcosx=sinx\frac{d}{d\theta} \cos x = -\sin xddxcos2x=2cosxsinx\frac{d}{dx} \cos^2 x = -2 \cos x \sin x

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