Answer to Question #349478 in Differential Equations for Ankit

Question

27y-8(dy/DX)³=0

Answer 1

$27y-8(dy/dx)^3=0$

$dy/dx=\sqrt[3]{27y/8}=3\sqrt[3]{y}/2$

$\frac{dy}{\sqrt[3]{y}}=\frac{3}{2}dx$

$\frac{3}{2}y^{2/3}=\frac{3}{2}(x+C)$

$y=(x+C)^{3/2}$