Question #347709

A long thin steel railway tie is 10 yards at 60oF. What will be the length be when the temperature falls to -15oF?


Expert's answer

Given:

t1=60 ∘F=15.6 ∘Ct_1=60\:{^\circ\rm F}=15.6\:{^\circ\rm C}

t2=−15 ∘F=−26.1 ∘Ct_2=-15\:{^\circ\rm F}=-26.1\:{^\circ\rm C}


l=l0(1+αΔT)l=l_0(1+\alpha \Delta T)

l=10 yd(1+11∗10−6∗(−26.1−15.6))=9.995 ydl={10\:\rm yd(1+11*10^{-6}*(-26.1-15.6))}\\=9.995\:\rm yd


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