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Question #345688
Calculate the Laplace transform of
• (t) integral from (0 to t) (T)e^(T)dT
Expert's answer
L
{
f
}
(
s
)
=
∫
0
∞
f
(
t
)
e
−
s
t
d
t
{\cal L}\{f\}(s)=\int_0^{\infty}f(t)e^{-st}dt
L
{
f
}
(
s
)
=
∫
0
∞
f
(
t
)
e
−
s
t
d
t
L
{
t
∫
0
t
T
e
T
d
T
}
(
s
)
=
∫
0
∞
t
∫
0
t
T
e
T
d
T
e
−
s
t
d
t
{\cal L}\{t\int_0^tTe^TdT\}(s)=\int_0^{\infty}t\int_0^tTe^TdTe^{-st}dt
L
{
t
∫
0
t
T
e
T
d
T
}
(
s
)
=
∫
0
∞
t
∫
0
t
T
e
T
d
T
e
−
s
t
d
t
=
∫
0
∞
t
(
1
+
e
t
(
t
−
1
)
)
e
−
s
t
d
t
=
3
s
−
1
s
2
(
s
−
1
)
3
=\int_0^{\infty}t(1+e^t(t-1))e^{-st}dt=\frac{3s-1}{s^2(s-1)^3}
=
∫
0
∞
t
(
1
+
e
t
(
t
−
1
))
e
−
s
t
d
t
=
s
2
(
s
−
1
)
3
3
s
−
1
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