Question #341070

The rate of increase of the population of bateria in a culture is proportional to the number of bacteria at any given instant. Assume the initial count of bacteria is 1000 and after 1 hour the amount is 1200. Find (i) the number of bacteria present immediately after 5 hours. (iii) the time lapse before the number reaches 4000


1
Expert's answer
2022-05-18T09:06:05-0400

f(t)=f0ektf(t)=f_0e^{kt}

f0=1000f_0=1000

t=1 hour=60 min

1200=1000e60k1200=1000e^{60k}

k=(ln(1200/1000))/60=0.003k=(ln(1200/1000))/60=0.003

1. t=5hours=300 min

f(300)=1000e0.003x300=2489f(300)=1000e^{0.003x300}=2489

2.4000=1000e0.003t4000=1000e^{0.003t}

t=(ln(4000/1000))/0.003=462mint=(ln(4000/1000))/0.003=462 min


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