(D^4 − 18D^3 + 119D^2 − 342D + 360)y = 0
Solution
For given homogeneous equation the characteristic equation is
λ4 – 18 λ3 + 119 λ2– 342 λ + 360 = 0
λ4 – 3 λ3 – 15 λ3 + 45 λ2 + 74 λ2 – 222 λ – 120 λ + 360 = 0
(λ – 3)( λ3 – 15 λ2 + 74 λ – 120 ) = 0
(λ – 3)( λ3 – 4 λ2 – 11 λ2 + 44 λ + 30 λ – 120 ) = 0
(λ – 3) (λ – 4) ( λ2 – 11 λ + 30 ) = 0
(λ – 3) (λ – 4) (λ – 5) (λ – 6) = 0
So solutions of this equation are λ1 = 3, λ2 = 4, λ3 = 5, λ4 = 6.
Therefore the general solution of the given differential equation is
y(x) = Ae3x + Be4x + Ce5x + De6x , where A, B, C, D are arbitrary constants.
Answer
y(x) = Ae3x + Be4x + Ce5x + De6x
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