(dy)/(dx) = - x/(2y)
Question
"\\frac {dy} {dx}=-\\frac {x} {2y}"
Solution.
We have:
"\\frac {dy} {dx}=-\\frac {x} {2y}"
"2y\\,dy=-x\\,dx"
"\\int {2y} \\ dy=\\int {-x}\\ dx"
"2\\frac {y^2} {2}=-\\frac {x^2} {2} + C"
"y^2=-\\frac {x^2} {2} + C"
"y=\\pm \\sqrt{-\\frac {x^2} {2} + C}"
"y^2=-\\frac {x^2} {2} + C" is the general integral in an implicit form.
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